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65 lines
1.6 KiB
Python
65 lines
1.6 KiB
Python
import re
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import cn2an
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import opencc
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converter = opencc.OpenCC('zaonhe')
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# List of (Latin alphabet, ipa) pairs:
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_latin_to_ipa = [(re.compile('%s' % x[0]), x[1]) for x in [
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('A', 'ᴇ'),
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('B', 'bi'),
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('C', 'si'),
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('D', 'di'),
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('E', 'i'),
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('F', 'ᴇf'),
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('G', 'dʑi'),
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('H', 'ᴇtɕʰ'),
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('I', 'ᴀi'),
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('J', 'dʑᴇ'),
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('K', 'kʰᴇ'),
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('L', 'ᴇl'),
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('M', 'ᴇm'),
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('N', 'ᴇn'),
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('O', 'o'),
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('P', 'pʰi'),
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('Q', 'kʰiu'),
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('R', 'ᴀl'),
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('S', 'ᴇs'),
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('T', 'tʰi'),
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('U', 'ɦiu'),
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('V', 'vi'),
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('W', 'dᴀbɤliu'),
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('X', 'ᴇks'),
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('Y', 'uᴀi'),
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('Z', 'zᴇ')
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]]
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def _number_to_shanghainese(num):
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num = cn2an.an2cn(num).replace('一十','十').replace('二十', '廿').replace('二', '两')
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return re.sub(r'((?:^|[^三四五六七八九])十|廿)两', r'\1二', num)
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def number_to_shanghainese(text):
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return re.sub(r'\d+(?:\.?\d+)?', lambda x: _number_to_shanghainese(x.group()), text)
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def latin_to_ipa(text):
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for regex, replacement in _latin_to_ipa:
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text = re.sub(regex, replacement, text)
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return text
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def shanghainese_to_ipa(text):
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text = number_to_shanghainese(text.upper())
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text = converter.convert(text).replace('-','').replace('$',' ')
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text = re.sub(r'[A-Z]', lambda x: latin_to_ipa(x.group())+' ', text)
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text = re.sub(r'[、；：]', '，', text)
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text = re.sub(r'\s*，\s*', ', ', text)
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text = re.sub(r'\s*。\s*', '. ', text)
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text = re.sub(r'\s*？\s*', '? ', text)
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text = re.sub(r'\s*！\s*', '! ', text)
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text = re.sub(r'\s*$', '', text)
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return text
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